<PRE><B>Question 226028</B>
one salt solution is 15% and another is 20% salt.
 How many cubic centimeters of each solution must be mixed to obtain 50 cubic centimeters of 16% solution?
:
Let x = amt of 20% solution
:
The resulting amt is to be 50 cu/cm, therefore
(50-x) = amt of 15% solution
:
Using the decimal equiv, write an amt of salt equation
:
.20x + .15(50-x) = .16(50)
:
.20x + 7.5 - .15x = 8 
:
.20x - .15x = 8 - 7.5
:
.05x = .5
x = {{{.5/.05}}}
x = 10 cu/cm of 20% salt 
and
50 - 10 = 40 cu/cm of 15% salt
:
:
check
.2(10) + .15(40) = .16(50)
2 + 6 = 8

</PRE>