Question 226107
Find two consecutive odd integers such that the square of the larger one is 25 more than 8 times the smaller one.

{{{x}}} = the smaller odd integer
{{{y}}} = the next consecutive integer

{{{(x + 2)^2 = 25 + 8x}}}
{{{(x + 2)(x + 2) = 25 + 8x}}}
{{{(x^2 + 2x + 2x + 4) = 25 + 8x}}}
{{{(x^2 + 4x + 4) = 25 + 8x}}}
{{{x^2 - 4x - 21 = 0}}}
*[invoke solve_quadratic_equation 1, -4, -21]

Staci :]