Question 226096
Find two consecutive even integers whose sum is 117.


Step 1.  Let n be the first even integer.


Step 2.  Let n+2 be the next consecutive even integer.


Step 3.  Then n+n+2=117 since two consecutive even integers whose sum is 117.


Step 4.  Solving yields the following steps.


{{{2n+2=117}}


Subtract 2 from both sides of the equation


{{{2n=115}}}


Divide by 2 to both sides of the equation


{{{2n/2=115/2}}}


{{{n=17.5}}} but this is not an even integer.


Step 5.  ANSWER:  There is no solution to this problem.   Note the addition of two even integers will not yield an odd integer.


I hope the above steps and explanation were helpful.


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Respectfully,
Dr J

http://www.FreedomUniversity.TV