Question 225416
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Though you did not include the proper parentheses, I assume that you meant


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{6x-8}\ =\ x]


Square both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \6x-8\ =\ x^2]


Standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 -6x+8=0]


Just solve the quadratic.  Remember to check both roots to make sure you did not introduce any extraneous roots because of the squaring operation used in the solution process.


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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2\sqrt{x+2}-3\ =\ 7]


Add 3 to both sides, then square both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4(x+2)\ =\ 100]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x + 2\ =\ 25]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 23]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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