Question 225337
Our given equations are:
{{{A+B=90}}}
{{{20+3A=2B+50}}}
Solve the first one for a variable:
{{{A=90-B}}}
Plug this into the second equation:
{{{20+3(90-B)=2B+50}}}
Distribute the 3:
{{{20+270-3B=2B+50}}}
Combine like terms:
{{{290-3B=2B+50}}}
Move the -3B to the other side by adding it:
{{{290=5B+50}}}
Move the 50 over by subtracting it:
(((240=5B}}}
Divide both sides by 5:
{{{B=48}}}
Plug this back into our equation:
{{{A=90-48}}}
{{{A=42}}}
So, {{{A=42}}} and {{{B=48}}}.