Question 225321
Assuming:
{{{(32x^2+24x-11)/4x}}}
We can rewrite to this:
{{{(32x^2/4x+24x/4x-11/4x)}}
Then we simplify what we can: {{{32/4=8}}}, and {{{x^2/x=x}}}. So, our first term becomes:
{{{(8x+24x/4x-11/4x)}}}
The second term: {{{24/4=6}}} and {{{x/x=1}}}. So, the second term becomes:
{{{(8x+6-11/4x)}}}
The last term: 11/4 does not give us an integer, so we leave it in the 11/4 form. And the x term does not cancel with another x, so our final answer remains:
{{{(8x+6-11/4x)}}}