Question 225305
We need to get the #s on one side and the x terms on the other.
So, move the 10 to the other side by subtracting it from both:
{{{3x+10-10=2x-5-10}}}
{{{3x=2x-15}}}
Then move the 2x over to the other side by subtracting it from both sides:
{{{3x-2x=2x-2x-15}}}
{{{x=-15}}}, which is our answer.