Question 225127
Move the 3 to the other side:
{{{x^2 - 2x-8 >0}}}
Then we can factor:
{{{(x-4)(x+2)>0}}}
To finish solving, set both of these as follows:
{{{(x-4)>0}}}, {{{(x+2)>0}}}
Solve for x by moving the numbers to the other side:
{{{x>4}}}, {{{x>-2}}}
Those are your answers.