Question 225094
The perimeter of a standard high school basketball court is 268ft.  The length is 34ft longer than the width.  Find the dimensions of the court.


Step 1.  The perimeter P means adding up all the four sides of a rectangle.


Step 2.  Let w be the width.


Step 3.  Let w+34 be the length since the length is 34 ft longer than the width.


Step 4.  Then, P=w+w+w+34+w+34=268.


Step 5.  Solving yields the following steps


*[invoke explain_simplification "w+w+w+34+w+34=268" ]


For w=50 , then w+34=84 and P=2(50+84)=268 which is a true statement.


Step 6.  ANSWER:  The width is 50 feet and he length is 84 feet.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J


drjctu@gmail.com


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