Question 225092
All we're doing here is solving for 'y':



{{{(1/3)(y+2)+3x=7y}}} Start with the given equation.



{{{y+2+9x=21y}}} Multiply EVERY term (outside the parenthesis) the LCD 3 to clear out the fraction.



{{{y+9x=21y-2}}} Subtract {{{2}}} from both sides.



{{{y=21y-2-9x}}} Subtract {{{9x}}} from both sides.



{{{y-21y=-2-9x}}} Subtract {{{21y}}} from both sides.



{{{-20y=-2-9x}}} Combine like terms on the left side.



{{{-20y=-9x-2}}} Rearrange the terms.



{{{y=(-9x-2)/(-20)}}} Divide both sides by {{{-20}}} to isolate {{{y}}}.



{{{y=(-9x)/(-20)-2/(-20)}}} Break up the fraction.



{{{y=(9/20)x+1/10}}} Reduce.



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Answer:


So the solution is {{{y=(9/20)x+1/10}}}