<PRE><B>Question 225063</B>
Using synthetic division we can factor the numerator:
(Disregard the periods, I was trying to get the spacing to look a bit better).
3|1 -3 1 -3
..|..+3 0 +3
 -----------
....1  0 1  0 
Thus the numerator is: {{{(x-3)(x^2+1)}}}

So, our fraction is:
{{{((x-3)(x^2+1))/(x^2+1)}}}
The {{{(x^2+1)}}} cancels to leave us with:
{{{(x-3)}}}</PRE>