Question 224993
(1) 4x^2 -4x +3=0,,,,solve  using  quadratic  formula
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a=4,,,,b=(-4),,,,,,c=3
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x=[-(-4) +/- sqrt{ (-4)^2 -4 (4)(3)}]/2(4)
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x=[ 4 +/- sqrt -32 ] /8
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x= 1/2 +/- 5.7i/8
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x= .5 + .707i,,,,.5 - .707i
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check,,4(.5+.707i)^2 -4(.5+.707i) +3=0
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4(.25 +.707i -.5) -2 - 2,828i +3 =0
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1 + 2.828i -2-2 -2.828i +3 =0
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1-2-2+3=0,,,,,,,,,,  ok
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(2) x^2 +12x -64 = 0,,,,,factor
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(x+16)(x-4) = 0
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x= 4,,,-16
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check,,,(4),,,16 +48 -64 =0,,,,ok
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(-16),,,256 - 192 -64 =0,,,,,ok
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