Question 29944
line (-1/3)x-y=2 --> y = (-1/3)x-2, so its gradient is (-1/3). Any line perpendicular to this has gradient of 3 (2 perpendicular gradients, m*n = -1)


So we have x=-5, y=-1, m=3...find c from y=mx+c and that will give you the equation of the line.


jon.