<PRE><B>Question 224773</B>
Graph the equation using slope and y-intercept


  {{{7y+4x=7}}}


Step 1.  Need to put above line in slope intercept form given as y=mx+b where m is the slope and b is the y-intercept b when x=0 or at point (0,b).


Step 3.  Solving for y in {{{7y+4x=7}}} yields the following steps.

{{{7y+4x=7}}}


Subtract 4x from both sides of the equation


{{{7y+4x-4x=7-4x}}}


{{{7y=-4x+7}}}


Divide by 7 to both sides of the equation


{{{7y/7=-4x/7+7/7}}}


{{{y=-4x/7+1}}}


Step 4.  Comparing {{{y=-4x/7+1}}} with {{{y=mx+b}}}  we have the slope {{{m=-4/7}}} and y-intercept {{{b=1}}} when x=0 or y-intercept is at (0,1)


Step 5.  Starting with (0,1) we move seven units to the right and four units down since this is a slope of -4/7.  Thus, the other point is (0+7,1-4) or (7,-3)


Step 6.  ANSWER:  The graph is shown below using the points (0,1) and (7,-3)


{{{graph(400,400, -10,10, -10, 10, -4x/7+1)}}}


I hope the above steps and explanation were helpful.


For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J

http://www.FreedomUniversity.TV
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