Question 224805
x^2-x=-2
x^2-x-2=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(1+-sqrt[-1^2-4*1*-2])/2*1
x=(1+-sqrt[1+8])/2
x=(1+-sqrt9)/2
x=(1+-3)/2
x=(1+3)/2
x=4/2
x=2 ans.
x=(1-3)/2
x=-2/2
x=-1 ans.