Question 224749
The vertex form of a parabola's equation is generally expressed as :
{{{ y= a(x-h)^2+k }}}
where (h,k) is the vertex
.
You were given:
{{{y=-(x-6)^2-1}}}
which if we could rewrite as:
{{{y=-(x-6)^2+(-1)}}}
From inspection, because it is in "vertex form" we see that the vertex is at
(6,-1)