Question 224612
Given the parabola y = -(x – 6)^2 – 1, determine each of the following.
Identify whether the parabola y = -(x – 6)^2 – 1 opens up or down.
It opens down, the x^2 term is negative.
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Identify the vertex of the parabola y = -(x – 6)^2 – 1
y = -x^2 + 12x - 37
The vertex is at x = -b/2a = -12/-2 = 6
At x = 6, y = -1 --> vertex at (6,-1)
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Identify the x-intercept(s)
*[invoke solve_quadratic_equation -1,12,-37]
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Identify the y-intercept(s)
-37