Question 224569
{{{sqrt(1-3x)=x+1}}}


Step 1. Square both sides of the equation to get rid of the square root sign.


{{{(sqrt(1-3x))^2=(x+1)^2}}}


{{{1-3x=x^2+2x+1}}}


Step 2.  Add -1+3x to both sides of the equation to get a quadratic equation


{{{1-3x-1+3x=x^2+2x+1-1+3x}}}


{{{0=x^2+5x}}}


Step 3.  Factor out the x


{{{x(x+5)=0}}}


{{{x=0}}} and {{{x+5=0}}} or {{{x=-5}}}


Step 4.  ANSWER:  The solutions are {{{x=0}}} and {{{x=-5}}}


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J


http://www.FreedomUniversity.TV
http://www.Facebook.com/FreedomUniversityTV
http://www.Twitter.com/FreedomUTV