<PRE><B>Question 224515</B>
Your first part is correct.  f(g(x)) means to substitute g(x) = 6x into the formula for f, so {{{f(g(x))=sqrt(6x+3) }}}.  However, what you did next was NOT correct.  You have a SQUARE ROOT, NOT a SQUARE! Do NOT square it!!!


f(g(1)) means to substitute 1 in place of the x.  


This would be {{{f(g(1))= sqrt(6+3)=sqrt(9)=3}}}


f(g(1)) = 3


R^2</PRE>