Question 224484
Okay, from your statment this is what I assume is going on:
{{{2<=(x+2)/5<=5}}}
So, we need to solve for {{{x}}}, first thing to do is get rid of the 5 in the denominator. We can do this by multiplying all parts of the equation by 5.
{{{5*2<=5*((x+2)/5)<=5*5}}}
This yields:
{{{10<=x+2<=25}}}, since the 5 in the middle term canceled.
Next, move the 2 by subtracting it from all sides.
{{{10-2<=x+2-2<=25-2}}}
This gives us the final answer:
{{{8<=x<=23}}}.
Good luck!