Question 224337
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Let *[tex \Large n] be the number of nickels.  Then *[tex \Large 2n] is the number of dimes because there are twice as many dimes as nickels.  And there are *[tex \Large 4n] pennies because there are twice as many dimes as pennies.


The value of *[tex \Large 4n] pennies is *[tex \Large (0.01)4n\ =\ 0.04n] dollars.  The value of *[tex \Large 2n] dimes is *[tex \Large (0.1)2n\ =\ 0.2n] dollars.  The value of *[tex \Large n] nickels is *[tex \Large (.05)n\ =\ 0.05n]


The total value of all the coins is $2.32, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.04n\ +\ 0.2n\ +\ 0.05n\ =\ 2.32]


Just solve for *[tex \Large n] to get the number of nickels, then the rest should be simple.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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