<PRE><B>Question 224314</B>
Phelp me solve by elimination


5x+6y=3  (Equation 1) or multiplying by 2 to both sides of the equation yields 10x+12y=6
10x+12y=6  (Equation 2)


Answer is ordered pair integers or fractions


Equation 1 is identical to Equation 2 if you multiply Equation 1 by 2.  Therefore you have an infinite set of solutions.   When I do multiply Equation 1 by 2 and subtract Equation 2 from multiplied version of Equation 1, I get 0=0 on both sides of the equation while eliminating both the x and y terms.


ANSWER:  There are an infinite set of solutions satisfying the system of equations.


I hope the above steps were helpful. 


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