Question 224200
If three times the smaller of two consecutive integers is added to four times the larger, the result is 39. Find the smaller integer.


Step 1.  Let n be the smaller integer.


Step 2.  Let n+1 be the larger and next consecutive integer.


Step 3.  Let 3n be three times the smaller integer.


Step 4.  Let 4(n+1) be four times the larger integer.


Step 5.  Then 3n+4(n+1)=39 since three times the smaller of two consecutive integers is added to four times the larger will result in 39.


Step 6.  Solving the equation in Step yields the following steps:


*[invoke explain_simplification "3n+4(n+1)=39" ]


With n=5, then n+1=6 and check the sum 3*5+4*6=15+24=39...which is a true statement.


Step 7.  ANSWER:  The integers are  5 and 6


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J


drjctu@gmail.com


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