Question 224306
Let x= speed of great blue heron

x+10 = speed of Canada goose


{{{t=D/r}}}


Time of heron = Time of goose

{{{80/x=120/(x+10) }}}


If {{{a/b=c/d}}}, then {{{ad=bc}}}
If {{{80/x=120/(x+10)}}}, then {{{80(x+10)=120x}}}


80x+800=120x
800=40x
x=20 mph for the great blue heron
x+10= 30 mph for the Canadian goose


Check:  120/30= 4 hours  Canadian goose
80/20 = 4 hours great blue heron.

It checks!!


R^2


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus