Question 224160
log(4+3^5x)=log(8)
log(4+3^5x)-log(8) = 0


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log[(4+3^(5x))/8] = 0
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(4+3^(5x))/8 = 10^0
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4+3^(5x) = 8
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3^(5x) = 4
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5x*log(3) = log(4)
5x = [log(4)]/[log(3)]
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x = (1/5)[log(4)]/[log(3)]
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x = 0.2524
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Cheers,
Stan H.