Question 224002
Well, Teri, let's do it step by step, it's not that hard
:
Phyllis invested 54,000 dollars, a portion earning a simple interest rate of 
percent 4% per year and the rest earning a rate of 6% per year. 

After one year the total interest earned on these investments was 2760 dollars.
 How much money did she invest at each rate?
:
Let x = amt invested at 6%
It gives the total as $54,000, therefore we can say:
(54000-x) = amt invested at 4%
;
A total interest equation
.06x + .04(54000-x) = 2760
:
.06x + 2160 - .04x = 2760
:
.06x - .04x = 2760 - 2160
:
.02x = 600
x = {{{600/.02}}}
x = $30,000 invested at 6%
then
54000 - 30000 = $24,000 invested at 4%
;
:
We can check our solution
.06(30000) + .04(24000)
1800 + 960 = 2760, confirms our solution