Question 224017
The sum of twice a first number and five times a second number is 92. If the second number is subtracted from five times the first number the result is 14. Find the numbers.


Step 1.  Let x be first number.


Step 2.  Let y be the second number.


Step 3.  Let 2x+5y=92 since the sum of twice a first number and five times a second number is 92.


Step 4.  Also, 5x-y=14 since the second number is subtracted from five times the first number the result is 14.


Step 5.  We have a system of equations given by Steps 3 and 4.


2x+5y=92
5x-y=14


*[invoke linear_substitution "x", "y", 2, 5, 92, 5, -1, 14 ]


Step 6.  ANSWER:  The numbers are 6 and 16.


I hope the above steps and explanation were helpful. 


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