Question 223524
This Company manufactures three types of dweezle, type K, Type Z, and type F. Each type of dweezle is composed of two compounds, iron and zinc.
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Each pound of type K is 12 ounces of iron and 4 ounces of zinc
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while each pound of type Z is 12 ounces of zinc and 4 ounces of iron.
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Type F requires 8 ounces of each per pound.
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Zinc is somewhat more difficult to work with, making type Z more costly to produce.
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A pound of type Z requires 9.6 man-hours to produce 

while a pound of type K requires only 6 man-hours
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 and type F only 8.
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The company has 125 pounds of zinc and 175 pounds of iron and only 2180 man-hours available for production,
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 how many of type K and type Z can the Company make?
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This IS a pain, the guy that wrote this, ought to get back on his medication.
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Let k, z, f  be the no. of each items made, respectively
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The zinc amt equation
4k + 12z + 8f = 125
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The iron amt equation
12k + 4z + 8f = 175
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The man-hour equation
6k + 9.6z + 8f = 2180
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I checked this using the matrix feature on my calc and there are not 3 positive 
solutions to this.  Something is not right here