Question 223987
{{{(64/81)^(-1/2)}}}
By applying "exponent rules" we can make it positive by moving it to the denominator:
{{{1/(64/81)^(1/2)}}}
And, of course, an exponent of 1/2 is actually a "square root":
{{{1/sqrt(64/81)}}}
{{{1/(8/9)}}}
{{{9/8)}}}
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{{{(1/1000)^(1/3)}}}
Anything raised to the 1/3 power is actually a "cube root"
{{{(1/1000)^(1/3) =  1/10}}}