Question 223934
Find the two numbers whose sum is 50 and whose product is 621.


Step 1.  Let x be one number.


Step 2.  Let 50-x be the other number since the sum is 50.


Step 3.  Then, x(50-x)=621 or {{{-x^2+50x-621=0}}} or {{{x^2-50x+621=0}}}


Step 4.  To solve, use quadratic formula given as


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


where a=1, b=-50, and c=621


*[invoke quadratic "x", 1, -50, 621 ]


(please ignore the graph since it's the numbers are out of scale)


Step 5.  ANSWER:  The numbers are 23 and 27.


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J