Question 223833
Find the slope if it exists x+3y=6


Step 1.  We need to put the equation in slope-intercept form given as y=mx+b where m is the slope and b is the y-intercept at x=0 or at point (0,b).


Step 2.  Given {{{x+3y=6}}}, then subtract x from both sides of the equation


{{{x+3y-x=6-x}}}


{{{3y=-x+6}}}


Divide 3 to both sides of the equation


{{{3y/3=-x/3+6/3}}}


{{{y=-x/3+2}}}


Step 3.  The equation {{{y=-x/3+2}}} is in slope-intercept form where the slope {{{m=-1/3}}} and the y-intercept {{{b=2}}}.


Step 4.  ANSWER:  The slope {{{m=-1/3}}} exists.


I hope the above steps were helpful.


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http://www.FreedomUniversity.TV/courses/Trigonometry.


Good luck in your studies!


Respectfully,
Dr J