Question 223775
A Straight line has the equation {{{x-2y=12}}} and it meets the axes at A and B. Find the distance of the mid-point of AB from the origin,
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x-2y = 12
x-intercept is at y = 0
x = 12
y-intercept is at x = =
y-intercept = -6
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A(12,0)
B(0,-6)
Midpoint is (6,-3) ( =1/2 of x and of y)
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Distance from Origin = {{{sqrt(6^2 + 3^2)}}}
= {{{sqrt(45)}}}
= {{{3sqrt(5)}}}