Question 223762
How do you find all zeros of f, including complex zeros given f(x)= {{{2x^3-7x^2+12x+8}}}
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I found a real root x = -1/2 by graphing.
Dividing that out leaves
{{{2x^2 - 8x + 16}}}
{{{x^2 - 4x + 8 = 0}}}
*[invoke solve_quadratic_equation 1,-4,8]
--> 2 +/- 2i