Question 223742
{{{x^2-2x-13=0}}}


To solve, use the quadratic formula given as


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


where a=1, b=-2, and c=-13.


*[invoke quadratic "x", 1, -2, -13 ]\


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J