Question 223729
Take note that the same 'x's and 'y's are being used here. So we can use this fact to eliminate one variable so we can solve for the other. There are many ways to do this, but I'll use substitution.


{{{x+y=32}}} Start with the second equation



{{{y=32-x}}} Subtract 'x' from both sides.



{{{2x+2y=64}}} Move onto the first equation.



{{{2x+2highlight((32-x))=64}}} Plug in {{{y=32-x}}}. In other words, replace each 'y' with {{{32-x}}} (this is possible since the two are equal).



So we now have the equation {{{2x+2(32-x)=64}}} which now consists of one variable. Simply solve this equation to find 'x'. I'll let you do that (let me know if you still need help). Once you find 'x', plug that value into {{{y=32-x}}} to find 'y'.