Question 223653
{{{y=2(x-5)^2+63}}}
I'm going to put this into standard form first:
{{{y=2(x^2-10x+25)+63}}}
{{{y=2x^2-20+50+63}}}
{{{y=2x^2-20+113}}}
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Axis of symmetry from standard form equation is given as 
{{{x=-b/2a}}}
{{{x=20/4}}}
{{{highlight(x=5)}}}
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Note that you could also read it off directly from the vertex form:
{{{x=-h}}} where h is -5.
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Good Luck,
tutor_paul@yahoo.com