Question 223555
A younger brother left his house on foot.
:
 Six minutes later his older brother followed him on a bicycle.
:
 If the younger brother is going 50 meters a minute and the older brother is 
going 200 meters a minute, how many minutes will it take for the older brother
 to catch up to the younger brother?
:
 Can you please explain how to solve this problem using a linear equation
:
Let t = time for older brother to catch up
then 
(t+6) = time for the younger brother to be caught (he started 6 min sooner)
:
When this happens they both will have traveled the same distance
write a distance equation: dist = speed * time
:
older's dist = younger's dist
200t = 50(t+6)
200t = 50t + 300
200t - 50t = 300
150t = 300
t = {{{300/150}}}
t = 2 min
:
:
Check solution by finding the distance of each
200*2 = 400 m
50*(2+6) = 400 m