Question 223523
{{{(1-i)*(3+2i)}}} Start with the given expression.



{{{(1)(3)+(1)(2i)+(-i)(3)+(-i)(2i)}}} FOIL.



{{{3+2i-3i-2i^2}}} Multiply.



{{{3+2i-3i-2(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{3+2i-3i+2}}} Multiply.



{{{5-i}}} Combine like terms.



So {{{(1-i)*(3+2i)=5-i}}}.