Question 28983
6p - 18             3p - 9
_______ divided by _________
   9p               p^2 + 2p

=[6(p-3)/9p] divided by [3(p-3)/p(p+2)]
= [6(p-3)/9p] multiplied by [p(p+2)/3(p-3)]
= [6(p-3)/9p] X [p(p+2)/3(p-3)]
= [6p(p-3)(p+2)]/[(9X3)p(p-3)](multiplying nr by nr and dr by dr)
=2(p+2)/9  (canceling 3p(p-3) )