<PRE><B>Question 223239</B>
log (x2y4/z3)
= 2log(x) + 4log(y) - 3log(z)
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log8 (x3y4/z5)
= 3log8(x) + 4log8(y) - 3log(z)
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log2 (x/y2z3)
= log2(x) - 2log2(y) - 3log2(z)
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logx243=5
 logx(243) = 5
x^5 = 243
x = 3
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Cheers,
Stan H.
</PRE>