Question 223222
Write {{{root(3,16)}}} in the form {{{2^k}}}, k∊Q
<pre><font size = 4 color = "indigo"><b>
Use the rule: {{{root(n,x)=x^(1/n)}}}

{{{root(3,16)=16^(1/3)}}}

Now use the fact that {{{16=2^4}}},

{{{root(3,16)=16^(1/3)=(2^4)^(1/3)}}}

Use the rule that {{{(x^m)^n=x^(mn)}}}

{{{root(3,16)=16^(1/3)=(2^4)^(1/3)=2^(4/3)}}}

Edwin</pre>