Question 223206
{{{2^x=5^(x+1)}}}
Take the log of both sides
{{{log(2^x) = log(5^(x+1))}}}
{{{x*log(2) = (x+1)*log(5)}}}
log(2) and log(5) are just constants.
x*log(2) = x*log(5) + log(5)
x*log(2) - x*log(5) = log(5)
x*(log(2) - log(5)) = log(5)
x = log(5)/log(0.4)
x = ~ -1.75647