Question 223001
Find three consecutive even integers whose sum is 36.


Step 1.  Let n be an even integer.


Step 2.  Let n+2 and n+4 be the next two consecutive even integers.


Step 3.  Then n+n+2+n+4=36 since the sum of these three even integers is 36.


Step 4.  Solving yields the following steps


{{{3n+6=36}}}


Subtract 6 from both sides of the equation


{{{3n-6=36-6}}}


{{{3n=30}}}


Divide by 3 to both sides of the equation


{{{3n/3=30/3}}}


{{{n=10}}} {{{n+2=12}}} nad {{{n+4=14}}}.  Not these three even integers add up to 36.


Step 5.  ANSWER:  The three consecutive even integers are 10, 12, and 14.



I hope the above steps and explanation were helpful. 


For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry. 


Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.


Respectfully, 
Dr J