Question 223003
What would the quadratic eqation be with the roots 2/3 and 4. i got this question on a test and i didnt know how to do it can someone help please?


Step 1.  Since you know these are roots they satisfy the following equation:


{{{(x-2/3)(x-4)=0}}}


Step 2.  Use the FOIL method to multiply out the terms and to get rid of the parenthesis.



{{{(x-2/3)(x-4)=x*x-4*x-2x/3+(-2/3)*(-4)}}}



{{{(x-2/3)(x-4)=x^2-4x-2x/3+8/3}}}


Combine the x-terms and put in common denominator


{{{(x-2/3)(x-4)=x^2-(4+2/3)x+8/3}}}


{{{(x-2/3)(x-4)=x^2-(12/3+2/3)x+8/3}}}


{{{(x-2/3)(x-4)=x^2-14x/3+8/3}}}


Step 3.  ANSWER:  {{{(x-2/3)(x-4)=x^2-14x/3+8/3}}}


I hope the above steps and explanation were helpful. 


For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry. 


Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.


Respectfully, 
Dr J