Question 222984
find four consecutive integers such that the sum of the first and third is 200
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The numbers are close, and they add to 200, so they're about 100.
98 and 102 = 200.
98,100,102,104
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The hard way:
n, n+2, n+4, n+6
n + (n+4) = 200
2n + 4 = 200
2n = 196
n = 98
etc.