Question 222888
I think they gave your 4 equations just to scare you a bit. It turns out that the four equations {{{5x*3y=180}}}, {{{x^2+y^2=40}}}, {{{8x-8y=32}}}, and {{{12x/(4y)=1}}} are a hyperbola, a circle, and two straight lines respectively. Since {{{8x-8y=32}}} and {{{12x/(4y)=1}}} are equations of lines, you need to satisfy all 4 equations, and the intersection of two lines is either going to give you a) no solutions, b) infinite solutions, or c) 1 solution, this means that your best bet is to solve the system {{{system(8x-8y=32,12x/(4y)=1)}}}



Note: you should find that there is only one solution to the system of two equations above, which would mean that there is only one solution to the given system of four equations.