Question 29906
{{{ (x-3)/((4x-5)(x+1)) }}}
since no number in the denom can be zero, set each part of it equal to zero.

{{{ 4x-5 =0 }}} and {{{ x+1 = 0 }}}
{{{ 4x = 5 }}} and {{{ x = -1 }}}
{{{ x = 5/4 }}} and {{{ x = -1 }}}
These are the values which are excluded, or that make the fraction 'Undefined'