Question 222770
Find FOUR consecutive integers whose sum is 50.


Step 1.  Let n be an integer.


Step 2.  Let n+1, n+2, n+3 be the next three consecutive integers.


Step 3.  Then,  n+n+1+n+2+n+3=50 since the sum of the four consecutive integers is 50.


Step 4.  Solving the equation in Step 3 yields the following steps


{{{4n+6=50}}}


Subtract 6 from both sides of the equation


{{{4n+6-6=50-6}}}


{{{4n=44}}}


Divide 4 to both sides of the equation


{{{4n/4=44/4}}}


{{{n=11}}}  {{{n+1=12}}}   {{{n+2=13}}}   and   {{{n+3=14}}}


And 11+12+13+14=50 which is a true statement.


Step 5.  ANSWER:  The four consecutive integers are 11, 12, 13, and 14.


I hope the above steps were helpful.


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Good luck in your studies!


Respectfully,
Dr J