Question 222729

{{{-2x+3y=8}}} Start with the given equation.



{{{3y=8+2x}}} Add {{{2x}}} to both sides.



{{{3y=2x+8}}} Rearrange the terms.



{{{y=(2x+8)/(3)}}} Divide both sides by {{{3}}} to isolate y.



{{{y=(2/3)x+8/3}}} Break up the fraction.



So the equation {{{y=(2/3)x+8/3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2/3}}} and the y-intercept is {{{b=8/3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,\frac{8}{3}\right)]