Question 222574
Let  x  =  amt  of  pure  water  added (0% antifreeze)
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(0 %) x + 1(100%) = (1+x)(95%)
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0*x + 1+1.00 = .95 +.95x
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1=.95 +.95x
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.05 = .95x
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.053 = x,,,,  in  gallons
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Check
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0(.053) +1 = .95(1.053)= 1,,,,,ok
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